(5x-2)*(11-x)=0

Solution for (5x-2)*(11-x)=0 equation:

(5x-2)(11-x)=0

We add all the numbers together, and all the variables

(5x-2)(-1x+11)=0

We multiply parentheses ..

(-5x^2+55x+2x-22)=0

We get rid of parentheses

-5x^2+55x+2x-22=0

We add all the numbers together, and all the variables

-5x^2+57x-22=0

a = -5; b = 57; c = -22;
Δ = b2-4ac
Δ = 572-4·(-5)·(-22)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-53}{2*-5}=\frac{-110}{-10}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+53}{2*-5}=\frac{-4}{-10}
=2/5
$