(5x-2)(3x-4)=15(x-1)(x-1)-13x

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Solution for (5x-2)(3x-4)=15(x-1)(x-1)-13x equation: 



(5x-2)(3x-4)=15(x-1)(x-1)-13x

We move all terms to the left:

(5x-2)(3x-4)-(15(x-1)(x-1)-13x)=0

We multiply parentheses ..

(+15x^2-20x-6x+8)-(15(x-1)(x-1)-13x)=0



We calculate terms in parentheses: -(15(x-1)(x-1)-13x), so:

15(x-1)(x-1)-13x

We add all the numbers together, and all the variables

-13x+15(x-1)(x-1)

We multiply parentheses ..

15(+x^2-1x-1x+1)-13x

We multiply parentheses

15x^2-15x-15x-13x+15

We add all the numbers together, and all the variables

15x^2-43x+15

Back to the equation:

-(15x^2-43x+15)



We get rid of parentheses

15x^2-15x^2-20x-6x+43x+8-15=0

We add all the numbers together, and all the variables

17x-7=0

We move all terms containing x to the left, all other terms to the right

17x=7

x=7/17

x=7/17

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