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(5x-2)(-10+4x)=14
We move all terms to the left:
(5x-2)(-10+4x)-(14)=0
We add all the numbers together, and all the variables
(5x-2)(4x-10)-14=0
We multiply parentheses ..
(+20x^2-50x-8x+20)-14=0
We get rid of parentheses
20x^2-50x-8x+20-14=0
We add all the numbers together, and all the variables
20x^2-58x+6=0
a = 20; b = -58; c = +6;
Δ = b2-4ac
Δ = -582-4·20·6
Δ = 2884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2884}=\sqrt{4*721}=\sqrt{4}*\sqrt{721}=2\sqrt{721}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-2\sqrt{721}}{2*20}=\frac{58-2\sqrt{721}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+2\sqrt{721}}{2*20}=\frac{58+2\sqrt{721}}{40} $
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