(5x-16/x-3)-(x-4/x-3)=0

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Solution for (5x-16/x-3)-(x-4/x-3)=0 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x-x-(16/x)+4/x-3+3 = 0

5*x-x-16*x^-1+4/x-3+3 = 0

4*x^1-12*x^-1 = 0

(4*x^2-12*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-12*x^0) = 0

x^1

4*x^2-12 = 0

4*x^2-12 = 0

DELTA = 0^2-(-12*4*4)

DELTA = 192

DELTA > 0

x = (192^(1/2)+0)/(2*4) or x = (0-192^(1/2))/(2*4)

x = 3^(1/2) or x = -3^(1/2)

x in { -3^(1/2), 3^(1/2)}

x in { -3^(1/2), 3^(1/2) }

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