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(5x-16)=(2x)50
We move all terms to the left:
(5x-16)-((2x)50)=0
determiningTheFunctionDomain (5x-16)-2x50=0
We add all the numbers together, and all the variables
-2x^50+(5x-16)=0
We get rid of parentheses
-2x^50+5x-16=0
We do not support expression: x^50
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