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(5x-1)(4x+2)=110
We move all terms to the left:
(5x-1)(4x+2)-(110)=0
We multiply parentheses ..
(+20x^2+10x-4x-2)-110=0
We get rid of parentheses
20x^2+10x-4x-2-110=0
We add all the numbers together, and all the variables
20x^2+6x-112=0
a = 20; b = 6; c = -112;
Δ = b2-4ac
Δ = 62-4·20·(-112)
Δ = 8996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8996}=\sqrt{4*2249}=\sqrt{4}*\sqrt{2249}=2\sqrt{2249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{2249}}{2*20}=\frac{-6-2\sqrt{2249}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{2249}}{2*20}=\frac{-6+2\sqrt{2249}}{40} $
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