(5x-1)(3x-2)=4

Solution for (5x-1)(3x-2)=4 equation:

(5x-1)(3x-2)=4

We move all terms to the left:

(5x-1)(3x-2)-(4)=0

We multiply parentheses ..

(+15x^2-10x-3x+2)-4=0

We get rid of parentheses

15x^2-10x-3x+2-4=0

We add all the numbers together, and all the variables

15x^2-13x-2=0

a = 15; b = -13; c = -2;
Δ = b2-4ac
Δ = -132-4·15·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*15}=\frac{-4}{30}
=-2/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*15}=\frac{30}{30}
=1
$