(5x+9)+(33+x)=(4x+32)

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Solution for (5x+9)+(33+x)=(4x+32) equation: 



(5x+9)+(33+x)=(4x+32)

We move all terms to the left:

(5x+9)+(33+x)-((4x+32))=0

We add all the numbers together, and all the variables

(5x+9)+(x+33)-((4x+32))=0

We get rid of parentheses

5x+x-((4x+32))+9+33=0



We calculate terms in parentheses: -((4x+32)), so:

(4x+32)

We get rid of parentheses

4x+32

Back to the equation:

-(4x+32)



We add all the numbers together, and all the variables

6x-(4x+32)+42=0

We get rid of parentheses

6x-4x-32+42=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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