If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5x+7)(x-1)+(5x+3)(x+4)=26x+8
We move all terms to the left:
(5x+7)(x-1)+(5x+3)(x+4)-(26x+8)=0
We get rid of parentheses
(5x+7)(x-1)+(5x+3)(x+4)-26x-8=0
We multiply parentheses ..
(+5x^2-5x+7x-7)+(5x+3)(x+4)-26x-8=0
We add all the numbers together, and all the variables
(+5x^2-5x+7x-7)-26x+(5x+3)(x+4)-8=0
We get rid of parentheses
5x^2-5x+7x-26x+(5x+3)(x+4)-7-8=0
We multiply parentheses ..
5x^2+(+5x^2+20x+3x+12)-5x+7x-26x-7-8=0
We add all the numbers together, and all the variables
5x^2+(+5x^2+20x+3x+12)-24x-15=0
We get rid of parentheses
5x^2+5x^2+20x+3x-24x+12-15=0
We add all the numbers together, and all the variables
10x^2-1x-3=0
a = 10; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·10·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*10}=\frac{-10}{20} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*10}=\frac{12}{20} =3/5 $
| 16+32x+4=-32x+40 | | 2x+3x-4x+5x=18 | | 29/v=2 | | X=3x-7+1 | | 41+4x=161 | | 4x+8+4=-16-4x | | 2x+27+45=90 | | 68/u=3 | | s-7=7/8 | | 10b=108 | | (x+1)*(x-2)-3(x+5)=3-5x | | h-8=1/5 | | 3/5+k=7 | | r+5/6=9 | | 6-5.3=p | | z-1/9=8 | | 71+x-11+x-22=180 | | r-1/10=7 | | d7/2=5 | | 5.6-1.9=w | | 90-5x=x-5 | | 3.9+2.2=n | | d-3=4.8 | | r-5/8=6 | | 7a-12=7 | | x/100=15/95 | | 227=t-357 | | 7=y-5/(4.28) | | 2z=622 | | 26c=832 | | 6=s/22 | | 3-7y/2=4-y |