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(5x+6)/(3x-9)=7/3
We move all terms to the left:
(5x+6)/(3x-9)-(7/3)=0
Domain of the equation: (3x-9)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x!=9
x!=9/3
x!=3
x∈R
(5x+6)/(3x-9)-(+7/3)=0
We get rid of parentheses
(5x+6)/(3x-9)-7/3=0
We calculate fractions
(15x+18)/(9x-27)+(-21x+63)/(9x-27)=0
We multiply all the terms by the denominator
(15x+18)+(-21x+63)=0
We get rid of parentheses
15x-21x+18+63=0
We add all the numbers together, and all the variables
-6x+81=0
We move all terms containing x to the left, all other terms to the right
-6x=-81
x=-81/-6
x=13+1/2
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