(5x+6)(-3x+4)=0

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Solution for (5x+6)(-3x+4)=0 equation:



(5x+6)(-3x+4)=0
We multiply parentheses ..
(-15x^2+20x-18x+24)=0
We get rid of parentheses
-15x^2+20x-18x+24=0
We add all the numbers together, and all the variables
-15x^2+2x+24=0
a = -15; b = 2; c = +24;
Δ = b2-4ac
Δ = 22-4·(-15)·24
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*-15}=\frac{-40}{-30} =1+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*-15}=\frac{36}{-30} =-1+1/5 $

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