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(5x+5)+(7x^2)=75
We move all terms to the left:
(5x+5)+(7x^2)-(75)=0
determiningTheFunctionDomain 7x^2+(5x+5)-75=0
We get rid of parentheses
7x^2+5x+5-75=0
We add all the numbers together, and all the variables
7x^2+5x-70=0
a = 7; b = 5; c = -70;
Δ = b2-4ac
Δ = 52-4·7·(-70)
Δ = 1985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1985}}{2*7}=\frac{-5-\sqrt{1985}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1985}}{2*7}=\frac{-5+\sqrt{1985}}{14} $
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