(5x+5)(x+1)=0

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Solution for (5x+5)(x+1)=0 equation: 



(5x+5)(x+1)=0

We multiply parentheses ..

(+5x^2+5x+5x+5)=0

We get rid of parentheses

5x^2+5x+5x+5=0

We add all the numbers together, and all the variables

5x^2+10x+5=0

a = 5; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-10}{10}=-1$

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