(5x+4)/2=(2x+2)/3+16

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Solution for (5x+4)/2=(2x+2)/3+16 equation: 



(5x+4)/2=(2x+2)/3+16

We move all terms to the left:

(5x+4)/2-((2x+2)/3+16)=0

We calculate fractions


(15x+12)/()+(-((2x+2)*2)/()=0



We calculate terms in parentheses: +(-((2x+2)*2)/(), so:

-((2x+2)*2)/(

We multiply all the terms by the denominator


-((2x+2)*2)



We calculate terms in parentheses: -((2x+2)*2), so:

(2x+2)*2

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

-4x-4

Back to the equation:

+(-4x-4)



We get rid of parentheses

(15x+12)/()-4x-4=0

We multiply all the terms by the denominator


(15x+12)-4x*()-4*()=0

We add all the numbers together, and all the variables

(15x+12)-4x*()=0

We get rid of parentheses

15x-4x*()+12=0

We move all terms containing x to the left, all other terms to the right

15x-4x*()=-12

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