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(5x+35)(4x-8)=x
We move all terms to the left:
(5x+35)(4x-8)-(x)=0
We add all the numbers together, and all the variables
-1x+(5x+35)(4x-8)=0
We multiply parentheses ..
(+20x^2-40x+140x-280)-1x=0
We get rid of parentheses
20x^2-40x+140x-1x-280=0
We add all the numbers together, and all the variables
20x^2+99x-280=0
a = 20; b = 99; c = -280;
Δ = b2-4ac
Δ = 992-4·20·(-280)
Δ = 32201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-\sqrt{32201}}{2*20}=\frac{-99-\sqrt{32201}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+\sqrt{32201}}{2*20}=\frac{-99+\sqrt{32201}}{40} $
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