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(5x+3)x=344
We move all terms to the left:
(5x+3)x-(344)=0
We multiply parentheses
5x^2+3x-344=0
a = 5; b = 3; c = -344;
Δ = b2-4ac
Δ = 32-4·5·(-344)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-83}{2*5}=\frac{-86}{10} =-8+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+83}{2*5}=\frac{80}{10} =8 $
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