(5x+3)/2=(7x+5)/3

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Solution for (5x+3)/2=(7x+5)/3 equation: 



(5x+3)/2=(7x+5)/3

We move all terms to the left:

(5x+3)/2-((7x+5)/3)=0

We calculate fractions


5x/()+(-((7x+5)*2)/()=0



We calculate terms in parentheses: +(-((7x+5)*2)/(), so:

-((7x+5)*2)/(

We multiply all the terms by the denominator


-((7x+5)*2)



We calculate terms in parentheses: -((7x+5)*2), so:

(7x+5)*2

We multiply parentheses

14x+10

Back to the equation:

-(14x+10)



We get rid of parentheses

-14x-10

Back to the equation:

+(-14x-10)



We get rid of parentheses

5x/()-14x-10=0

We multiply all the terms by the denominator


5x-14x*()-10*()=0

We add all the numbers together, and all the variables

5x-14x*()=0

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