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(5x+3)(x+7)=0
We multiply parentheses ..
(+5x^2+35x+3x+21)=0
We get rid of parentheses
5x^2+35x+3x+21=0
We add all the numbers together, and all the variables
5x^2+38x+21=0
a = 5; b = 38; c = +21;
Δ = b2-4ac
Δ = 382-4·5·21
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-32}{2*5}=\frac{-70}{10} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+32}{2*5}=\frac{-6}{10} =-3/5 $
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