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(5x+3)(5x+3)=21
We move all terms to the left:
(5x+3)(5x+3)-(21)=0
We multiply parentheses ..
(+25x^2+15x+15x+9)-21=0
We get rid of parentheses
25x^2+15x+15x+9-21=0
We add all the numbers together, and all the variables
25x^2+30x-12=0
a = 25; b = 30; c = -12;
Δ = b2-4ac
Δ = 302-4·25·(-12)
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{21}}{2*25}=\frac{-30-10\sqrt{21}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{21}}{2*25}=\frac{-30+10\sqrt{21}}{50} $
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