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(5x+3)(4x+10)=x
We move all terms to the left:
(5x+3)(4x+10)-(x)=0
We add all the numbers together, and all the variables
-1x+(5x+3)(4x+10)=0
We multiply parentheses ..
(+20x^2+50x+12x+30)-1x=0
We get rid of parentheses
20x^2+50x+12x-1x+30=0
We add all the numbers together, and all the variables
20x^2+61x+30=0
a = 20; b = 61; c = +30;
Δ = b2-4ac
Δ = 612-4·20·30
Δ = 1321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{1321}}{2*20}=\frac{-61-\sqrt{1321}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{1321}}{2*20}=\frac{-61+\sqrt{1321}}{40} $
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