(5x+2y)(5x-2y)=0

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Solution for (5x+2y)(5x-2y)=0 equation:


Simplifying
(5x + 2y)(5x + -2y) = 0

Multiply (5x + 2y) * (5x + -2y)
(5x * (5x + -2y) + 2y * (5x + -2y)) = 0
((5x * 5x + -2y * 5x) + 2y * (5x + -2y)) = 0

Reorder the terms:
((-10xy + 25x2) + 2y * (5x + -2y)) = 0
((-10xy + 25x2) + 2y * (5x + -2y)) = 0
(-10xy + 25x2 + (5x * 2y + -2y * 2y)) = 0
(-10xy + 25x2 + (10xy + -4y2)) = 0

Reorder the terms:
(-10xy + 10xy + 25x2 + -4y2) = 0

Combine like terms: -10xy + 10xy = 0
(0 + 25x2 + -4y2) = 0
(25x2 + -4y2) = 0

Solving
25x2 + -4y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y2' to each side of the equation.
25x2 + -4y2 + 4y2 = 0 + 4y2

Combine like terms: -4y2 + 4y2 = 0
25x2 + 0 = 0 + 4y2
25x2 = 0 + 4y2
Remove the zero:
25x2 = 4y2

Divide each side by '25'.
x2 = 0.16y2

Simplifying
x2 = 0.16y2

Take the square root of each side:
x = {-0.4y, 0.4y}

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