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(5x+20)(4x+25)=180
We move all terms to the left:
(5x+20)(4x+25)-(180)=0
We multiply parentheses ..
(+20x^2+125x+80x+500)-180=0
We get rid of parentheses
20x^2+125x+80x+500-180=0
We add all the numbers together, and all the variables
20x^2+205x+320=0
a = 20; b = 205; c = +320;
Δ = b2-4ac
Δ = 2052-4·20·320
Δ = 16425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16425}=\sqrt{225*73}=\sqrt{225}*\sqrt{73}=15\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(205)-15\sqrt{73}}{2*20}=\frac{-205-15\sqrt{73}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(205)+15\sqrt{73}}{2*20}=\frac{-205+15\sqrt{73}}{40} $
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