(5x+2)-7=6-(5x+4)-8

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Solution for (5x+2)-7=6-(5x+4)-8 equation: 



(5x+2)-7=6-(5x+4)-8

We move all terms to the left:

(5x+2)-7-(6-(5x+4)-8)=0

We get rid of parentheses

5x-(6-(5x+4)-8)+2-7=0



We calculate terms in parentheses: -(6-(5x+4)-8), so:

6-(5x+4)-8

determiningTheFunctionDomain
-(5x+4)+6-8

We add all the numbers together, and all the variables

-(5x+4)-2

We get rid of parentheses

-5x-4-2

We add all the numbers together, and all the variables

-5x-6

Back to the equation:

-(-5x-6)



We add all the numbers together, and all the variables

5x-(-5x-6)-5=0

We get rid of parentheses

5x+5x+6-5=0

We add all the numbers together, and all the variables

10x+1=0

We move all terms containing x to the left, all other terms to the right

10x=-1

x=-1/10

x=-1/10

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