(5x+10)/6=(8x+3)/7

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Solution for (5x+10)/6=(8x+3)/7 equation: 



(5x+10)/6=(8x+3)/7

We move all terms to the left:

(5x+10)/6-((8x+3)/7)=0

We calculate fractions


5x/()+(-((8x+3)*6)/()=0



We calculate terms in parentheses: +(-((8x+3)*6)/(), so:

-((8x+3)*6)/(

We multiply all the terms by the denominator


-((8x+3)*6)



We calculate terms in parentheses: -((8x+3)*6), so:

(8x+3)*6

We multiply parentheses

48x+18

Back to the equation:

-(48x+18)



We get rid of parentheses

-48x-18

Back to the equation:

+(-48x-18)



We get rid of parentheses

5x/()-48x-18=0

We multiply all the terms by the denominator


5x-48x*()-18*()=0

We add all the numbers together, and all the variables

5x-48x*()=0

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