(5x+1)/3=(2x-8)/2

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Solution for (5x+1)/3=(2x-8)/2 equation: 



(5x+1)/3=(2x-8)/2

We move all terms to the left:

(5x+1)/3-((2x-8)/2)=0

We calculate fractions


5x/()+(-((2x-8)*3)/()=0



We calculate terms in parentheses: +(-((2x-8)*3)/(), so:

-((2x-8)*3)/(

We multiply all the terms by the denominator


-((2x-8)*3)



We calculate terms in parentheses: -((2x-8)*3), so:

(2x-8)*3

We multiply parentheses

6x-24

Back to the equation:

-(6x-24)



We get rid of parentheses

-6x+24

Back to the equation:

+(-6x+24)



We get rid of parentheses

5x/()-6x+24=0

We multiply all the terms by the denominator


5x-6x*()+24*()=0

We add all the numbers together, and all the variables

5x-6x*()=0

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