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(5x+1)/(4x+2)=0
Domain of the equation: (4x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
4x!=-2
x!=-2/4
x!=-1/2
x∈R
(5x+1)=0
We get rid of parentheses
5x+1=0
We move all terms containing x to the left, all other terms to the right
5x=-1
x=-1/5
x=-1/5
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