(5x+1)(x+3)-8=(5x+1)(x+2)

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Solution for (5x+1)(x+3)-8=(5x+1)(x+2) equation: 



(5x+1)(x+3)-8=(5x+1)(x+2)

We move all terms to the left:

(5x+1)(x+3)-8-((5x+1)(x+2))=0

We multiply parentheses ..

(+5x^2+15x+x+3)-((5x+1)(x+2))-8=0



We calculate terms in parentheses: -((5x+1)(x+2)), so:

(5x+1)(x+2)

We multiply parentheses ..

(+5x^2+10x+x+2)

We get rid of parentheses

5x^2+10x+x+2

We add all the numbers together, and all the variables

5x^2+11x+2

Back to the equation:

-(5x^2+11x+2)



We get rid of parentheses

5x^2-5x^2+15x+x-11x+3-2-8=0

We add all the numbers together, and all the variables

5x-7=0

We move all terms containing x to the left, all other terms to the right

5x=7

x=7/5

x=1+2/5

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