(5x*5x)+43=(x-1)(5x+6)

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Solution for (5x*5x)+43=(x-1)(5x+6) equation: 



(5x*5x)+43=(x-1)(5x+6)

We move all terms to the left:

(5x*5x)+43-((x-1)(5x+6))=0

We add all the numbers together, and all the variables

(+5x*5x)-((x-1)(5x+6))+43=0

We get rid of parentheses

5x*5x-((x-1)(5x+6))+43=0

We multiply parentheses ..

-((+5x^2+6x-5x-6))+5x*5x+43=0



We calculate terms in parentheses: -((+5x^2+6x-5x-6)), so:

(+5x^2+6x-5x-6)

We get rid of parentheses

5x^2+6x-5x-6

We add all the numbers together, and all the variables

5x^2+x-6

Back to the equation:

-(5x^2+x-6)



Wy multiply elements

25x^2-(5x^2+x-6)+43=0

We get rid of parentheses

25x^2-5x^2-x+6+43=0

We add all the numbers together, and all the variables

20x^2-1x+49=0

a = 20; b = -1; c = +49;
Δ = b2-4ac
Δ = -12-4·20·49
Δ = -3919
Delta is less than zero, so there is no solution for the equation

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