(5x)2+8x=62

Solution for (5x)2+8x=62 equation:

(5x)2+8x=62

We move all terms to the left:

(5x)2+8x-(62)=0

We add all the numbers together, and all the variables

5x^2+8x-62=0

a = 5; b = 8; c = -62;
Δ = b2-4ac
Δ = 82-4·5·(-62)
Δ = 1304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1304}=\sqrt{4*326}=\sqrt{4}*\sqrt{326}=2\sqrt{326}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{326}}{2*5}=\frac{-8-2\sqrt{326}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{326}}{2*5}=\frac{-8+2\sqrt{326}}{10}
$