(5x)2+16x+2=0

Solution for (5x)2+16x+2=0 equation:

(5x)2+16x+2=0

We add all the numbers together, and all the variables

5x^2+16x+2=0

a = 5; b = 16; c = +2;
Δ = b2-4ac
Δ = 162-4·5·2
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-6\sqrt{6}}{2*5}=\frac{-16-6\sqrt{6}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+6\sqrt{6}}{2*5}=\frac{-16+6\sqrt{6}}{10}
$