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(5x)/(2x+1)=2/3
We move all terms to the left:
(5x)/(2x+1)-(2/3)=0
Domain of the equation: (2x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=-1
x!=-1/2
x!=-1/2
x∈R
5x/(2x+1)-(+2/3)=0
We get rid of parentheses
5x/(2x+1)-2/3=0
We calculate fractions
15x/(6x+3)+(-4x-2)/(6x+3)=0
We multiply all the terms by the denominator
15x+(-4x-2)=0
We get rid of parentheses
15x-4x-2=0
We add all the numbers together, and all the variables
11x-2=0
We move all terms containing x to the left, all other terms to the right
11x=2
x=2/11
x=2/11
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