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(5x)-((x)/(5))+((x+1)/(7))=(8x)
We move all terms to the left:
(5x)-((x)/(5))+((x+1)/(7))-((8x))=0
determiningTheFunctionDomain 5x-(x/5)+((x+1)/7)-8x=0
We add all the numbers together, and all the variables
5x-(+x/5)+((x+1)/7)-8x=0
We add all the numbers together, and all the variables
-3x-(+x/5)+((x+1)/7)=0
We get rid of parentheses
-3x-x/5+((x+1)/7)=0
We calculate fractions
(-7x^2)/()-3x+(((x+1)*5)/()=0
We calculate terms in parentheses: +(((x+1)*5)/(), so:We get rid of parentheses
((x+1)*5)/(
We multiply all the terms by the denominator
((x+1)*5)
We calculate terms in parentheses: +((x+1)*5), so:We get rid of parentheses
(x+1)*5
We multiply parentheses
5x+5
Back to the equation:
+(5x+5)
5x+5
Back to the equation:
+(5x+5)
(-7x^2)/()-3x+5x+5=0
We multiply all the terms by the denominator
(-7x^2)-3x*()+5x*()+5*()=0
We add all the numbers together, and all the variables
(-7x^2)-3x*()+5x*()=0
We get rid of parentheses
-7x^2-3x*()+5x*()=0
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