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(5x)(4x+10)=360
We move all terms to the left:
(5x)(4x+10)-(360)=0
We multiply parentheses
20x^2+50x-360=0
a = 20; b = 50; c = -360;
Δ = b2-4ac
Δ = 502-4·20·(-360)
Δ = 31300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31300}=\sqrt{100*313}=\sqrt{100}*\sqrt{313}=10\sqrt{313}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{313}}{2*20}=\frac{-50-10\sqrt{313}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{313}}{2*20}=\frac{-50+10\sqrt{313}}{40} $
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