(5w-2)(4+w)=0

Solution for (5w-2)(4+w)=0 equation:

(5w-2)(4+w)=0

We add all the numbers together, and all the variables

(5w-2)(w+4)=0

We multiply parentheses ..

(+5w^2+20w-2w-8)=0

We get rid of parentheses

5w^2+20w-2w-8=0

We add all the numbers together, and all the variables

5w^2+18w-8=0

a = 5; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·5·(-8)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-22}{2*5}=\frac{-40}{10}
=-4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+22}{2*5}=\frac{4}{10}
=2/5
$