(5w-2)(1-w)=0

Solution for (5w-2)(1-w)=0 equation:

(5w-2)(1-w)=0

We add all the numbers together, and all the variables

(5w-2)(-1w+1)=0

We multiply parentheses ..

(-5w^2+5w+2w-2)=0

We get rid of parentheses

-5w^2+5w+2w-2=0

We add all the numbers together, and all the variables

-5w^2+7w-2=0

a = -5; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·(-5)·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*-5}=\frac{-10}{-10}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*-5}=\frac{-4}{-10}
=2/5
$