(5w+6)(5+w)=0

Solution for (5w+6)(5+w)=0 equation:

(5w+6)(5+w)=0

We add all the numbers together, and all the variables

(5w+6)(w+5)=0

We multiply parentheses ..

(+5w^2+25w+6w+30)=0

We get rid of parentheses

5w^2+25w+6w+30=0

We add all the numbers together, and all the variables

5w^2+31w+30=0

a = 5; b = 31; c = +30;
Δ = b2-4ac
Δ = 312-4·5·30
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-19}{2*5}=\frac{-50}{10}
=-5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+19}{2*5}=\frac{-12}{10}
=-1+1/5
$