(5v-9)/2=14+(2v-7)/6

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Solution for (5v-9)/2=14+(2v-7)/6 equation:



(5v-9)/2=14+(2v-7)/6
We move all terms to the left:
(5v-9)/2-(14+(2v-7)/6)=0
We calculate fractions
5v/()+(-(14+(2v-7)*2)/()=0
We calculate terms in parentheses: +(-(14+(2v-7)*2)/(), so:
-(14+(2v-7)*2)/(
We multiply all the terms by the denominator
-(14+(2v-7)*2)
We calculate terms in parentheses: -(14+(2v-7)*2), so:
14+(2v-7)*2
determiningTheFunctionDomain (2v-7)*2+14
We multiply parentheses
4v-14+14
We add all the numbers together, and all the variables
4v
Back to the equation:
-(4v)
Back to the equation:
+(-4v)
We get rid of parentheses
5v/()-4v=0
We multiply all the terms by the denominator
5v-4v*()=0

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