(5v+4)(6+v)=0

Solution for (5v+4)(6+v)=0 equation:

(5v+4)(6+v)=0

We add all the numbers together, and all the variables

(5v+4)(v+6)=0

We multiply parentheses ..

(+5v^2+30v+4v+24)=0

We get rid of parentheses

5v^2+30v+4v+24=0

We add all the numbers together, and all the variables

5v^2+34v+24=0

a = 5; b = 34; c = +24;
Δ = b2-4ac
Δ = 342-4·5·24
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-26}{2*5}=\frac{-60}{10}
=-6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+26}{2*5}=\frac{-8}{10}
=-4/5
$