If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5v+38v=23v-11)
We move all terms to the left:
(5v+38v-(23v-11))=0
We calculate terms in parentheses: +(5v+38v-(23v-11)), so:We get rid of parentheses
5v+38v-(23v-11)
We add all the numbers together, and all the variables
43v-(23v-11)
We get rid of parentheses
43v-23v+11
We add all the numbers together, and all the variables
20v+11
Back to the equation:
+(20v+11)
20v+11=0
We move all terms containing v to the left, all other terms to the right
20v=-11
v=-11/20
v=-11/20
| 4t+2=2t=10 | | 6x^2×-5x+1=0 | | 6+3h=18 | | 1+8=13+6n | | 12-t=5 | | x+31=-4x+18 | | 1/8x-3/10=1/10+3/16x | | 3y^2+20y+32=0 | | 24+2y-5=11y-11-4y | | 24+2y=12+4y | | ((2x/5)-(3x/4))=3 | | −1/8(x–4)=–4 | | 3(3c-1)=7c+2 | | 12m-4m=16 | | -x+3(-2x+3)=-12 | | 1b+83=-3b-5 | | 2y+15=-11 | | 4(v-20)=-16 | | 12(n+11)(3n-4)=0 | | −18(x–4)=–4 | | 16-3k=7 | | 7q-5q=14 | | 4x-7+86=9x-4 | | 2x(-2+x+x^2)=0 | | 16-4q=-8 | | 5+6x-12=6x-12-4x | | 5(x-4)=22 | | 3/2x-5/3=1/2x-5 | | 2z-z=3z-1+z | | 4z+15=9z-20 | | -f/6+5=2 | | (12x^2+19x-21)/(4x-3)-(7x^2-175)/(x^2-25)=((3+x)5+(x+3))+(7+x^2))/(4) |