(5u/7u)-(3/2u)=1

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Solution for (5u/7u)-(3/2u)=1 equation: 


u in (-oo:+oo)

((5*u)/7)*u-((3/2)*u) = 1 // - 1

((5*u)/7)*u-((3/2)*u)-1 = 0

((5*u)/7)*u+(-3/2)*u-1 = 0

5/7*u^2-3/2*u-1 = 0

DELTA = (-3/2)^2-(-1*5/7*4)

DELTA = 143/28

DELTA > 0

u = ((143/28)^(1/2)+3/2)/(5/7*2) or u = (3/2-(143/28)^(1/2))/(5/7*2)

u = 7/10*((143/28)^(1/2)+3/2) or u = 7/10*(3/2-(143/28)^(1/2))

u in { 7/10*(3/2-(143/28)^(1/2)), 7/10*((143/28)^(1/2)+3/2) }

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