(5u-6)(8+u)=0

Solution for (5u-6)(8+u)=0 equation:

(5u-6)(8+u)=0

We add all the numbers together, and all the variables

(5u-6)(u+8)=0

We multiply parentheses ..

(+5u^2+40u-6u-48)=0

We get rid of parentheses

5u^2+40u-6u-48=0

We add all the numbers together, and all the variables

5u^2+34u-48=0

a = 5; b = 34; c = -48;
Δ = b2-4ac
Δ = 342-4·5·(-48)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-46}{2*5}=\frac{-80}{10}
=-8
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+46}{2*5}=\frac{12}{10}
=1+1/5
$