(5u-3)(2+u)=0

Solution for (5u-3)(2+u)=0 equation:

(5u-3)(2+u)=0

We add all the numbers together, and all the variables

(5u-3)(u+2)=0

We multiply parentheses ..

(+5u^2+10u-3u-6)=0

We get rid of parentheses

5u^2+10u-3u-6=0

We add all the numbers together, and all the variables

5u^2+7u-6=0

a = 5; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·5·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*5}=\frac{-20}{10}
=-2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*5}=\frac{6}{10}
=3/5
$