(5u-10)(2u+6)=0

Solution for (5u-10)(2u+6)=0 equation:

(5u-10)(2u+6)=0

We multiply parentheses ..

(+10u^2+30u-20u-60)=0

We get rid of parentheses

10u^2+30u-20u-60=0

We add all the numbers together, and all the variables

10u^2+10u-60=0

a = 10; b = 10; c = -60;
Δ = b2-4ac
Δ = 102-4·10·(-60)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*10}=\frac{-60}{20}
=-3
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*10}=\frac{40}{20}
=2
$