(5u+6)(8+u)=0

Solution for (5u+6)(8+u)=0 equation:

(5u+6)(8+u)=0

We add all the numbers together, and all the variables

(5u+6)(u+8)=0

We multiply parentheses ..

(+5u^2+40u+6u+48)=0

We get rid of parentheses

5u^2+40u+6u+48=0

We add all the numbers together, and all the variables

5u^2+46u+48=0

a = 5; b = 46; c = +48;
Δ = b2-4ac
Δ = 462-4·5·48
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-34}{2*5}=\frac{-80}{10}
=-8
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+34}{2*5}=\frac{-12}{10}
=-1+1/5
$