(5t-2)+(-2=+t)

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Solution for (5t-2)+(-2=+t) equation: 



(5t-2)+(-2=+t)

We move all terms to the left:

(5t-2)+(-2-(+t))=0

We get rid of parentheses

5t+(-2-(+t))-2=0



We calculate terms in parentheses: +(-2-(+t)), so:

-2-(+t)

determiningTheFunctionDomain
-(+t)-2

We get rid of parentheses

-t-2

We add all the numbers together, and all the variables

-1t-2

Back to the equation:

+(-1t-2)



We get rid of parentheses

5t-1t-2-2=0

We add all the numbers together, and all the variables

4t-4=0

We move all terms containing t to the left, all other terms to the right

4t=4

t=4/4

t=1

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