(5r+6+4r)+(r+3r)=(37+28)+r-r

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Solution for (5r+6+4r)+(r+3r)=(37+28)+r-r equation: 



(5r+6+4r)+(r+3r)=(37+28)+r-r

We move all terms to the left:

(5r+6+4r)+(r+3r)-((37+28)+r-r)=0

We add all the numbers together, and all the variables

(9r+6)+(+4r)-(65+r-r)=0

We get rid of parentheses

9r+4r-r+r+6-65=0

We add all the numbers together, and all the variables

13r-59=0

We move all terms containing r to the left, all other terms to the right

13r=59

r=59/13

r=4+7/13

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