(5r+30)/20=(3r-27)/3

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Solution for (5r+30)/20=(3r-27)/3 equation:



(5r+30)/20=(3r-27)/3
We move all terms to the left:
(5r+30)/20-((3r-27)/3)=0
We calculate fractions
5r/()+(-((3r-27)*20)/()=0
We calculate terms in parentheses: +(-((3r-27)*20)/(), so:
-((3r-27)*20)/(
We multiply all the terms by the denominator
-((3r-27)*20)
We calculate terms in parentheses: -((3r-27)*20), so:
(3r-27)*20
We multiply parentheses
60r-540
Back to the equation:
-(60r-540)
We get rid of parentheses
-60r+540
Back to the equation:
+(-60r+540)
We get rid of parentheses
5r/()-60r+540=0
We multiply all the terms by the denominator
5r-60r*()+540*()=0
We add all the numbers together, and all the variables
5r-60r*()=0

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