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(5p+2)(8p+7)=0
We multiply parentheses ..
(+40p^2+35p+16p+14)=0
We get rid of parentheses
40p^2+35p+16p+14=0
We add all the numbers together, and all the variables
40p^2+51p+14=0
a = 40; b = 51; c = +14;
Δ = b2-4ac
Δ = 512-4·40·14
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-19}{2*40}=\frac{-70}{80} =-7/8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+19}{2*40}=\frac{-32}{80} =-2/5 $
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