(5m-6)(3m+4)=0

Solution for (5m-6)(3m+4)=0 equation:

(5m-6)(3m+4)=0

We multiply parentheses ..

(+15m^2+20m-18m-24)=0

We get rid of parentheses

15m^2+20m-18m-24=0

We add all the numbers together, and all the variables

15m^2+2m-24=0

a = 15; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·15·(-24)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*15}=\frac{-40}{30}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*15}=\frac{36}{30}
=1+1/5
$