(5k+1)/(6)=(3k-2)/(3)

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Solution for (5k+1)/(6)=(3k-2)/(3) equation: 



(5k+1)/(6)=(3k-2)/(3)

We move all terms to the left:

(5k+1)/(6)-((3k-2)/(3))=0

We calculate fractions


5k/()+(-((3k-2)*6)/()=0



We calculate terms in parentheses: +(-((3k-2)*6)/(), so:

-((3k-2)*6)/(

We multiply all the terms by the denominator


-((3k-2)*6)



We calculate terms in parentheses: -((3k-2)*6), so:

(3k-2)*6

We multiply parentheses

18k-12

Back to the equation:

-(18k-12)



We get rid of parentheses

-18k+12

Back to the equation:

+(-18k+12)



We get rid of parentheses

5k/()-18k+12=0

We multiply all the terms by the denominator


5k-18k*()+12*()=0

We add all the numbers together, and all the variables

5k-18k*()=0

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